Simple Array Element Sum in Java

Problem:-

Given an array of integers, find the sum of its elements.

For example, if the array , , so return .

Function Description

Complete the simpleArraySum function in the editor below. It must return the sum of the array elements as an integer.

simpleArraySum has the following parameter(s):

• ar: an array of integers

Input Format

The first line contains an integer, , denoting the size of the array.
The second line contains  space-separated integers representing the array's elements.

Constraints

Output Format

Print the sum of the array's elements as a single integer.

Sample Input

6
1 2 3 4 10 11

Sample Output

31

Explanation

We print the sum of the array's elements: .

Solution:-

import java.io.*;

import java.math.*;

import java.text.*;

import java.util.*;

import java.util.regex.*;

public class Solution {

/*

* Complete the simpleArraySum function below.

*/

static int simpleArraySum(int[] ar) {

int arrayLength = ar.length;

int sum=0;

for (int arItr = 0; arItr < arrayLength; arItr++) {

sum+= ar[arItr];

}

return sum;

}

private static final Scanner scanner = new Scanner(System.in);

public static void main(String[] args) throws IOException {

BufferedWriter bufferedWriter = new BufferedWriter(new FileWriter(System.getenv("OUTPUT_PATH")));

int arCount = Integer.parseInt(scanner.nextLine().trim());

int[] ar = new int[arCount];

String[] arItems = scanner.nextLine().split(" ");

for (int arItr = 0; arItr < arCount; arItr++) {

int arItem = Integer.parseInt(arItems[arItr].trim());

ar[arItr] = arItem;

}

int result = simpleArraySum(ar);

bufferedWriter.write(String.valueOf(result));

bufferedWriter.newLine();

bufferedWriter.close();

}

}

Addition Of Two Numbers: Basic Java Program

Problem:-

Complete the function solveMeFirst to compute the sum of two integers.

Function prototype:

int solveMeFirst(int a, int b);

where,

• a is the first integer input.
• b is the second integer input

Return values

• sum of the above two integers

Sample Input

a = 2
b = 3

Sample Output

5

Explanation

The sum of the two integers  and  is computed as: .

Solution:-

import java.io.*;

import java.util.*;

import java.text.*;

import java.math.*;

import java.util.regex.*;

public class Solution {

static int solveMeFirst(int a, int b) {

return a+b;

    }

public static void main(String[] args) {

Scanner in = new Scanner(System.in);

int a;

a = in.nextInt();

int b;

b = in.nextInt();

int sum;

sum = solveMeFirst(a, b);

System.out.println(sum);

    }

}

The Calendar class is an abstract class that provides methods for converting between a specific instant in time and a set of calendar fields such as YEAR, MONTH, DAY_OF_MONTH, HOUR, and so on, and for manipulating the calendar fields, such as getting the date of the next week.

Problem:

The Calendar class is an abstract class that provides methods for converting between a specific instant in time and a set of calendar fields such as YEAR, MONTH, DAY_OF_MONTH, HOUR, and so on, and for manipulating the calendar fields, such as getting the date of the next week.

---

You are given a date. You just need to write the method, , which returns the day on that date. To simplify your task, we have provided a portion of the code in the editor.

For example, if you are given the date , the method should return  as the day on that date.

Input Format

A single line of input containing the space separated month, day and year, respectively, in    format.

Constraints

Output Format

Output the correct day in capital letters.

Sample Input

08 05 2015

Sample Output

WEDNESDAY

Explanation

The day on August th  was WEDNESDAY.

Solution:-

import java.io.*;

import java.math.*;

import java.security.*;

import java.text.*;

import java.util.*;

import java.util.concurrent.*;

import java.util.regex.*;

class Result {

/*

* Complete the 'findDay' function below.

*

* The function is expected to return a STRING.

* The function accepts following parameters:

* 1. INTEGER month

* 2. INTEGER day

* 3. INTEGER year

*/

public static String findDay(int month, int day, int year) {

String weekDay=null;

try{

String date=day+"/"+month+"/"+year;

Date date1=new SimpleDateFormat("dd/MM/yyyy").parse(date);

SimpleDateFormat simpleDateformat = new SimpleDateFormat("EEEE");

weekDay=simpleDateformat.format(date1).toUpperCase( );

}

catch(Exception ex)

{

System.out.println(ex);

}

return weekDay;

}

}

public class Solution {

public static void main(String[] args) throws IOException {

BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in));

BufferedWriter bufferedWriter = new BufferedWriter(new FileWriter(System.getenv("OUTPUT_PATH")));

String[] firstMultipleInput = bufferedReader.readLine().replaceAll("\\s+$", "").split(" ");

int month = Integer.parseInt(firstMultipleInput[0]);

int day = Integer.parseInt(firstMultipleInput[1]);

int year = Integer.parseInt(firstMultipleInput[2]);

String res = Result.findDay(month, day, year);

bufferedWriter.write(res);

bufferedWriter.newLine();

bufferedReader.close();

bufferedWriter.close();

}

}

error: unreported exception ParseException; must be caught or declared to be thrown

Put the parse calls in a try block (preferably each in their own), and then specify in the catch block what should happen if the parsing fails.

The format is:-

try {
 //The code you are trying to exception handle
}
catch (Exception e) {
 //The handling for the code
}