Problem:-
Given an array of integers, find the sum of its elements.
For example, if the array , , so return .
Function Description
Complete the simpleArraySum function in the editor below. It must return the sum of the array elements as an integer.
simpleArraySum has the following parameter(s):
- ar: an array of integers
Input Format
The first line contains an integer, , denoting the size of the array.
The second line contains space-separated integers representing the array's elements.
The second line contains space-separated integers representing the array's elements.
Constraints
Output Format
Print the sum of the array's elements as a single integer.
Sample Input
6
1 2 3 4 10 11
Sample Output
31
Explanation
We print the sum of the array's elements: .
Solution:-
import java.io.*;
import java.math.*;
import java.text.*;
import java.util.*;
import java.util.regex.*;
public class Solution {
/*
* Complete the simpleArraySum function below.
*/
static int simpleArraySum(int[] ar) {
int arrayLength = ar.length;
int sum=0;
for (int arItr = 0; arItr < arrayLength; arItr++) {
sum+= ar[arItr];
}
return sum;
}
private static final Scanner scanner = new Scanner(System.in);
public static void main(String[] args) throws IOException {
BufferedWriter bufferedWriter = new BufferedWriter(new FileWriter(System.getenv("OUTPUT_PATH")));
int arCount = Integer.parseInt(scanner.nextLine().trim());
int[] ar = new int[arCount];
String[] arItems = scanner.nextLine().split(" ");
for (int arItr = 0; arItr < arCount; arItr++) {
int arItem = Integer.parseInt(arItems[arItr].trim());
ar[arItr] = arItem;
}
int result = simpleArraySum(ar);
bufferedWriter.write(String.valueOf(result));
bufferedWriter.newLine();
bufferedWriter.close();
}
}
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