Day 2: Conditional Statements: Switch:-10 Days Of Javascript HackerRank Solution

Problem:-

Objective

In this challenge, we learn about switch statements. Check out the attached tutorial for more details.

Task

Complete the getLetter(s) function in the editor. It has one parameter: a string, , consisting of lowercase English alphabetic letters (i.e., a through z). It must return A, B, C, or D depending on the following criteria:

• If the first character in string  is in the set , then return A.
• If the first character in string  is in the set , then return B.
• If the first character in string  is in the set , then return C.
• If the first character in string  is in the set , then return D.

Hint: You can get the letter at some index  in  using the syntax s[i] or s.charAt(i).

Input Format

Stub code in the editor reads a single string denoting  from stdin.

Constraints

• , where  is the length of .
• String  contains lowercase English alphabetic letters (i.e., a through z) only.

Output Format

Return either A, B, C, or D according to the criteria given above.

Sample Input 0

adfgt

Sample Output 0

A

Explanation 0

The first character of string  is a. Because the given criteria stipulate that we print A any time the first character is in , we return A as our answer.

Solution:-

'use strict';

process.stdin.resume();

process.stdin.setEncoding('utf-8');

let inputString = '';

let currentLine = 0;

process.stdin.on('data', inputStdin => {

inputString += inputStdin;

});

process.stdin.on('end', _ => {

inputString = inputString.trim().split('\n').map(string => {

return string.trim();

});

main();

});

function readLine() {

return inputString[currentLine++];

}

function getLetter(s) {

let letter;

switch (true) {

case 'aeiou'.includes(s[0]):

letter = 'A';

break;

case 'bcdfg'.includes(s[0]):

letter = 'B';

break;

case 'hjklm'.includes(s[0]):

letter = 'C';

break;

case 'npqrstvwxyz'.includes(s[0]):

letter = 'D';

break;

}

return letter;

}

function main() {

const s = readLine();

console.log(getLetter(s));

}