Java Strings Introduction HackerRank Solution in Java

Problem:-

"A string is traditionally a sequence of characters, either as a literal constant or as some kind of variable." — Wikipedia: String (computer science)

This exercise is to test your understanding of Java Strings. A sample String declaration:

String myString = "Hello World!"

The elements of a String are called characters. The number of characters in a String is called the length, and it can be retrieved with the String.length() method.

Given two strings of lowercase English letters,  and , perform the following operations:

1. Sum the lengths of  and .
2. Determine if  is lexicographically larger than  (i.e.: does  come before  in the dictionary?).
3. Capitalize the first letter in  and  and print them on a single line, separated by a space.

Input Format

The first line contains a string . The second line contains another string . The strings are comprised of only lowercase English letters.

Output Format

There are three lines of output: 
For the first line, sum the lengths of  and . 
For the second line, write Yes if  is lexicographically greater than  otherwise print No instead. 
For the third line, capitalize the first letter in both  and  and print them on a single line, separated by a space.

Sample Input 0

hello
java

Sample Output 0

9
No
Hello Java

Explanation 0

String  is "hello" and  is "java".

 has a length of , and  has a length of ; the sum of their lengths is . 
When sorted alphabetically/lexicographically, "hello" precedes "java"; therefore,  is not greater than  and the answer is No.

When you capitalize the first letter of both  and  and then print them separated by a space, you get "Hello Java".

Solution:-

import java.io.*;

import java.util.*;

public class Solution {

public static void main(String[] args) {

Scanner sc=new Scanner(System.in);

String A=sc.next();

String B=sc.next();

/* Enter your code here. Print output to STDOUT. */

System.out.println(A.length()+B.length());

System.out.println(A.compareTo(B)>0?"Yes":"No");

System.out.println(A.substring(0, 1).toUpperCase()+A.substring(1, A.length())+" "+B.substring(0, 1).toUpperCase()+B.substring(1, B.length()));

}

}